Question

I have a table of three points. how do i find the average velocity?

Answer 1

What do you mean "table"? Are these points on a graph? Are these vectors?

Answer 2

well vectors i guess.

Answer 3

yes vectors. i have to get the average velocity of the last three seconds of something.

Answer 4

Okay, hmm. What is the graph about? Distance over time? Speed over time? Acceleration over time?

Answer 5

distance vs. time

Answer 6

Alright, then the slope of the vector is the speed (or velocity... whatever). Seeing as how you have 3 points and you need the average of the three seconds, I'd assume that it wants you to find the slope of all three vectors and them average them together for your answer

Answer 7

i mean i guess i could do that, but its gonna be b!tch doing that for 8+ points

Answer 8

If I could do it for you, I would ;) Do you still want help finishing off the question? :)

Answer 9

no i think i got it

Answer 10

I'm getting huge numbers here =( not exactly working out.

Answer 11

what are the vectors? We'll do one at a time :)

Answer 12

I know the answer already but I need the work to prove it. I have 20.7m and 3.0s
36.8m and 4.0s
57.5m and 5s
answer: 6.1m/s

Answer 13

shoot *16.1m/s

Answer 14

okay, so then since time is the x value and distance is the y value... your vectors are

<3,20.7>
<4,36.8>
<5,57.5>

Using simple (rise/run) formula to get the slope, ... your slopes are

20.7/3
36.8/4
and 57.5/5

Do you already have the answers to this division?

Answer 15

@zepdrix have any ideas how I should go about this?

Answer 16

6.9,9.2,and 11.5

Answer 17

.....? ooooookay, so then these are all connected! I see now!! I thought these were all completely separate vectors! Two seconds

Answer 18

alright

Answer 19

So the first 3 seconds are a constant speed then. During said time, the distance traveled is 20.7. Then the speed is increased and the next distance is 20.7+j=36.8. Lastly, the speed is increased again for the last second and the distance is increased to 36.8+k=57.5

Answer 20

Your true vectors are:

<3,20.7>
<1,j> because there is only one second increase
<1,k> because there is only one second increase

Answer 21

THESE are the vectors whose slopes average to equal 16.1

Answer 22

so j is
36.8-20.7=16.1

Answer 23

hmm ok

Answer 24

Do you understand where I'm getting all of these numbers from?

Answer 25

yes but why j? why just j why not k... this the last three second btw not like it matters... it's constant by one any how

Answer 26

you need k too. I was just so tired, I forgot to figure k out.

Answer 27

mmk

Answer 28

its 20.7

Answer 29

I get that it's the last three seconds. The first 3 seconds are all the same speed so, once you find the slopes of the vectors I gave you, you'll have the slope of the last of the first 3 seconds, the slope of 4, and the slope of 5

Answer 30

okay, so plug those back into your vectors

Answer 31

ok

Answer 32

now find the slope of

<3, 20.7>
<1, 16.1>
<1, 20.7>

Answer 33

20.7/3
16.1/1
20.7/1

Answer 34

6.9,16.1,and 20.7

Answer 35

If those don't average together to give you the right answer, then your answer is wrong or I need to drop my calculus class o.O

Answer 36

haha idk