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A photon has a frequency of 6.0x10^4 Hz. Calculate the energy(in joules) of 1 mole of photons all with this frequency. This is what I have so far: \(E=hf\\=(6.626 \times 10^{-34})(6 \times 10^4)\\=3.98 \times 10^{-29}\) then what i have to do next?
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You now have the energy of a single photon (in Joules). If you want one mole then you just draw on your knowledge that a mole one Avogadro's Number of a given thing. So you must multiply the value that you got by Avogadro's number: \[=3.98\times10^{-29}\times6.022141\times10^{23}\] \[=2.3968\times10^{-5}Joules\]
\[E = h \nu = h\frac{c}{\lambda}\]
thanks
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