write the expression in standard form 8-i / 8+i
i of imaginary?
yes
i got 7/2 - 9/2i as the answer
is this right?
Remember your Order of Operations. It is ALWAYS working. You did try to get it with spacing, but it is much more clear with parentheses. (8-i)/(8+i)
(8-i)/(8+i) is the question and my answer is 7/2 - 9/2i
on the book it didn't have paranthesis
It very often doesn't IN A BOOK. You are not writing the same way, here. ALWAYS write what you mean and make sure it says what you want. Trust no one - book or otherwise. Strive for clarity.
Show numerator and denominator separately. \(\dfrac{8-i}{8+i}\cdot \dfrac{8-i}{8-i} = \)
8-8i-i+i squared / 8-i+i-i squared
then i got 8-9i+(-1) / 1-(-1)
7-9i / 2 = 7/2-9/2i
No good. Please go over that again. \(\dfrac{8-i}{8+i} = \dfrac{8-i}{8+i}\cdot\dfrac{8-i}{8-i} = \dfrac{64 - 16i + i^{2}}{64 - i^{2}}\) Simplify and try again.
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