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OpenStudy (anonymous):
i of imaginary?
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
i got 7/2 - 9/2i as the answer
OpenStudy (anonymous):
is this right?
OpenStudy (tkhunny):
Remember your Order of Operations. It is ALWAYS working. You did try to get it with spacing, but it is much more clear with parentheses. (8-i)/(8+i)
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OpenStudy (anonymous):
(8-i)/(8+i) is the question and my answer is 7/2 - 9/2i
OpenStudy (anonymous):
on the book it didn't have paranthesis
OpenStudy (tkhunny):
It very often doesn't IN A BOOK. You are not writing the same way, here. ALWAYS write what you mean and make sure it says what you want. Trust no one - book or otherwise. Strive for clarity.
OpenStudy (tkhunny):
Show numerator and denominator separately.
\(\dfrac{8-i}{8+i}\cdot \dfrac{8-i}{8-i} = \)
OpenStudy (anonymous):
8-8i-i+i squared / 8-i+i-i squared
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OpenStudy (anonymous):
then i got 8-9i+(-1) / 1-(-1)
OpenStudy (anonymous):
7-9i / 2 = 7/2-9/2i
OpenStudy (tkhunny):
No good. Please go over that again.
\(\dfrac{8-i}{8+i} = \dfrac{8-i}{8+i}\cdot\dfrac{8-i}{8-i} = \dfrac{64 - 16i + i^{2}}{64 - i^{2}}\)
Simplify and try again.