How do you find the equation of a line when given two points?
first find the slope then plug one of the points into the point slope equation
\[y-y _{1}=m(x-x _{1})\]
y1 is the y part of the coordinate pair, x1 is the x part of the coordinate pair, and m is the slope
So if there was a problem such as Find the equation of the line passing through the points (-3,4) and (6,-2). How would you answer it?
first you'd do\[\frac{ -2-4 }{ 6-(-3) }\]
\[\frac{ -6 }{ 9 } = \frac{ -2 }{ 3 }\]
then you'd use the equation i gave you and plug 4 into y1, -3 into x1 and (-2/3) into m
\[y-4=-\frac{ 2 }{ 3 }(x-(-3))\]\[y-4=-\frac{ 2 }{ 3 }(x+3)\]
distribute the (-2/3) then get y by itself by adding
* adding 4
tell me what you get after you do that :)
Y= 2/3x+6
* -2/3x, but other than that perfect :)
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