Question

My problem is X^2-6x+10=0 and i know the answer is 3+i , 3-i Need step by step process, please thanks.

Answer 1

@gabz12 do you know quadratic formula?

Answer 2

\[x=\frac{ -b \pm \sqrt{b ^{2}-4ac} }{ 2a }\]

Answer 3

good, we know that quadratic equation is of the following form
\[ax^2+bx+c=0\]
Our equation is
\[x^2-6x+10=0\]
Can you plugin the values of a, b and c in the formula you posted.

Answer 4

\[x=\frac{ -(-6)\sqrt{-6^{2}-4(1)(10)} }{ 2(1)} \] ?

Answer 5

yes, just one thing. Inside the root it should be (-6)^2 not -(6)^2.

Answer 6

well that was my mistake then i kept getting \[\frac{ 6\pm \sqrt{-76} }{ 2 }\]

Answer 7

So now you know the issue

Answer 8

but now i got \[\frac{ 6\pm \sqrt{4i} }{ 2 }\]

Answer 9

you can bring out the 4 from the root and cancel the common term from numerator and denominator.

Answer 10

wouldnt i be left with \[6\pm i\]

Answer 11

\[\frac{6\pm \sqrt 4 i}{2}\]
\[\frac{6\pm 2i}{2}\]
divide both numerator terms by 2 and you will get your answer.

Answer 12

oh i see where my problem was thank you for your time this was very helpful!

Answer 13

You're welcome :)