Question

Inverse function of...

Answer 1

f(x) = \[\sqrt{x ^{2}+2x}\]

Answer 2

So far all I got is
\[x ^{2} = y(y +2)\]

Answer 3

@lyssaaaa yaaa 51!

Answer 4

@ganeshie8 @Compassionate @Preetha @inkyvoyd @kirbykirby @Miracrown @iGreen

Answer 5

You have \(y^2+2y+x^2=0\)

You can apply quadratic formula to isolate y.

A = 1
B = 2
C = \(x^2\)

Answer 6

Sorry... I mean \(y^2+2y-x^2=0\)

So \(C =-x^2\)

Answer 7

Does that help? @adamaero

Answer 8

yes thank you

Answer 9

\[y^2=x^2+2x\]
\[x^2+2x-y^2=0\]
solve for x using quadratic eqn

Answer 10

wouldn't it be better by completing the square?
\[y ^{-1}=\pm \sqrt{x^2-1}\]