Question

Help?

Answer 1

ya?

Answer 2

Solve the following quadratic equation using completing the square method , show all work. How many solutions will the quadratic have? How do you find the number of solutions without solving? The equation is x^2=-4x+5

Answer 3

It would be so awesome if you could help, @kaiden37! I reallllly need it

Answer 4

@Secret-Ninja You there?

Answer 5

@989freak can you please help me?

Answer 6

nope sorry

Answer 7

Ok, thanks anyway :)

Answer 8

@jim_thompson5910 help??

Answer 9

@aum @jgirl128 I reallllly need help!

Answer 10

What class is this for? Is it FLVS?

Answer 11

No, its for my Algebra class

Answer 12

Its a practice sheet :/ and i really wanna be able to understand everything on here

Answer 13

What grade is it for? Like, are you in Algebra 1, 9th grade? or another?

Answer 14

Im in 11th grade Algebra 2, sorry haha

Answer 15

Oh hoop! I'm not quite there yet. haha. Sorry for ot being able to help. :/ Hope you get help soon! :)

Answer 16

It's totally fine! :) thanks for trying c: do you know of anyone that can help?

Answer 17

@aum you think you can help me out?

Answer 18

Solve x^2 = -4x + 5 by completing the square.
Add 4x to both sides:
x^2 + 4x = 5
To complete the square, add (b/(2a))^2 to both sides where b is the coefficient of the x term and a is the coefficient of the x^2 term. Here, a = 1 and b = 4. b/(2a) = 4/2 = 2

Add the square of 2 or 4 to both sides:
x^2 + 4x + 4 = 5 + 4
(x + 2)^2 = 9
Take the square root on both sides:
\((x+2) = \pm 3 \)

Can you solve for the two values of x now?

Answer 19

Woah, this helped so much! thanks! is it solved now?

Answer 20

Im sorry, Im not the best at math :/

Answer 21

\((x+2) = \pm 3\)
x + 2 = -3 or x + 2 = +3
add -2 to both sides:
x = -5 or x = 1

So the solutions are: x = -5 and x = 1.

Answer 22

Thank you!! So there is two solutions? Also, how do you find the number of solutions with out solving?

Answer 23

"Solve the following quadratic equation ...." : x = -5 and x = 1
"How many solutions will the quadratic have?" Two
"How do you find the number of solutions without solving?" Find the discriminant. If the discriminant is zero, the quadratic will have one solution. In all other cases the quadratic will have two solutions.

Answer 24

x^2=-4x+5
x^2 + 4x - 5 = 0
a = 1, b = 4, c = -5
Discriminant = b^2 - 4ac = (4)^2 - 4(1)(-5) = 16 + 20 = 36.

Since the discriminant is NOT zero, this quadratic equation will have two solutions.