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Mathematics 9 Online
OpenStudy (anonymous):

Find the multiplicity of f(x) = x^3 + 7x^2 - 4x - 28

OpenStudy (anonymous):

a polynomial does not have a "multiplicity" zeros of a polynomial do, but not a polynomial

OpenStudy (anonymous):

I know the answer and this question has multiplicities of 1 but idk how to get to it.

OpenStudy (anonymous):

can you post the entire question just as it is written?

OpenStudy (anonymous):

Find the zeroes for each polynomial function and give the multiplicity for each zero. State whether the graph crosses the x-axis, or touches the x-axis and turns around, at each zero.

OpenStudy (anonymous):

that makes sense it is not really what you posted though is it?

OpenStudy (anonymous):

That's the question and there is an answer but it's one of the hard problems that I have no idea how to do. I did a couple ones earlier but i have no idea how to do this one.

OpenStudy (anonymous):

Example: f(x) = x^3 -2x^2 + x > x(x^2 - 2x + 1) >>x (x-1)^2 x=0 w/ multiplicity of 1 and x=1 w/ multiplicity of 2

OpenStudy (anonymous):

you need to find the zeros of that thing maybe you can factor it

OpenStudy (anonymous):

I need help factoring, I don't know what to take out first

OpenStudy (anonymous):

either there is a typo or you have to use a graphing calculator this does not factor here is a picture http://www.wolframalpha.com/input/?i=x^3+%2B+7x^2+-+4x+%2B28

OpenStudy (anonymous):

you can see that it only crosses the x axis once so there is only one zero

OpenStudy (anonymous):

It factors out to ( x +/- 2) and (x+7)

OpenStudy (anonymous):

and because it crosses there, not touches, the multiplicity of that zero is one

OpenStudy (anonymous):

not the one you wrote

OpenStudy (anonymous):

oh wait x^3 + 7x^2 -4x-28

OpenStudy (anonymous):

Screwed that -28 my bad

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