Find the multiplicity of f(x) = x^3 + 7x^2 - 4x - 28
a polynomial does not have a "multiplicity" zeros of a polynomial do, but not a polynomial
I know the answer and this question has multiplicities of 1 but idk how to get to it.
can you post the entire question just as it is written?
Find the zeroes for each polynomial function and give the multiplicity for each zero. State whether the graph crosses the x-axis, or touches the x-axis and turns around, at each zero.
that makes sense it is not really what you posted though is it?
That's the question and there is an answer but it's one of the hard problems that I have no idea how to do. I did a couple ones earlier but i have no idea how to do this one.
Example: f(x) = x^3 -2x^2 + x > x(x^2 - 2x + 1) >>x (x-1)^2 x=0 w/ multiplicity of 1 and x=1 w/ multiplicity of 2
you need to find the zeros of that thing maybe you can factor it
I need help factoring, I don't know what to take out first
either there is a typo or you have to use a graphing calculator this does not factor here is a picture http://www.wolframalpha.com/input/?i=x^3+%2B+7x^2+-+4x+%2B28
you can see that it only crosses the x axis once so there is only one zero
It factors out to ( x +/- 2) and (x+7)
and because it crosses there, not touches, the multiplicity of that zero is one
not the one you wrote
oh wait x^3 + 7x^2 -4x-28
Screwed that -28 my bad
Join our real-time social learning platform and learn together with your friends!