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Physics 9 Online
OpenStudy (anonymous):

An unsuspecting bird is coasting along in an easterly direction at 3.00 mph when a strong wind from the south imparts a constant acceleration of 0.400 m/s2. If the acceleration from the wind lasts for 3.60 s, find the magnitude, r, and direction, Theta, of the bird\'s displacement during this time period. (HINT: assume the bird is originally travelling in the x direction and there are 1609 m in 1 mile.) r= meters theta= _______degrees Now, assume the same bird is moving along again at 3.00 mph in an easterly direction but this time the acceleration given by the wind is at a 50.0 degree

OpenStudy (anonymous):

angle to the original direction of motion. if the magnitude of acceleration is 0.400m/s^2, find the displacement vector r, and the angle of the displacement, theta1. enter the components of the vector and angle below.(Assume the time interval is still 3.60s) r=___mihat+___mjhat? and what is theta1__degrees..

OpenStudy (anonymous):

i have no idea what to do, i think i have to use \[x=x _{o}+V _{o}t+1/2at ^{2}\]..am I supposed to use that, please help

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