OpenStudy (anonymous):

Find an equation for the nth term of the sequence. -3, -12, -48, -192, ...

3 years ago
OpenStudy (anonymous):

@ganeshie8 @aaronq @Opcode

3 years ago
zepdrix (zepdrix):

So what is the common ratio? Looks like each term is the previous term multiplied by some value.

3 years ago
zepdrix (zepdrix):

$\Large\rm r=\frac{a_2}{a_1}$ $\Large\rm r=?$

3 years ago
OpenStudy (mathmath333):

$$\large\rm its~~ geometric~~ progression~~ with~~ common~~ ratio(r) \\ \rm\large r=4~~ and ~~its ~~first ~~term(a)~~ is~~ -3$$ $$\rm \large ~~u ~~can~~ use ~~the ~~formula$$ $$\rm\large~~ nth~~ term= ~~ar^{(n-1)}$$

3 years ago
OpenStudy (mathmath333):

$$\rm\large r=\dfrac{-12}{-3}=\dfrac{-48}{-12}.....$$

3 years ago