Question

Another Absolute Value Question c; Please Help!

Answer 1

\[\left| 4(x+2) \right|+9 = 15\]

Answer 2

I subtract 9 from both sides and got \[\left| 4(x+2) \right|= 6 \]

Answer 3

@phi @Callisto @YanaSidlinskiy @Cpt.Sparz @Conqueror

Answer 4

@AngelWilliams16

Answer 5

Not good at math, srry.

Answer 6

I got

x = -1/2

and

x = -3.5 or -7/2

Answer 7

|4(x+2)|=6
|4x+8|=6
now we got two cases:
I).4x+8<0=>4x<-8=>x<-2=>x E (-∞;-2)
now to the module we change the sign:
-4x-8=6=>-4x=14=>x=-14/4=-3.5 which is good for the domain;
II).4x+8>0=>x>-2=>x E (-2;+∞)
now we keep the sign
4x+8=6=>4x=-2=>x=-1/2 which is not good for the domain
so the final answer is x=-3.5

Answer 8

where you see � is \[\pm \infty \]

Answer 9

the correct answer is -3.5 because it's in the domain

Answer 10

Ok thank you :)

Answer 11

your two answers x= -1 /2 and - 7/ 2 are correct

as a check, use x= -1/ 2 in the original
| 4(x+2) |+9 = 15
| 4(-0.5+2) | + 9 = ? 15
| 4(1.5) | + 9
|6| + 9
6+9
15
yes that worked. now x= -7 /2 (or -3.5)

| 4(-3.5+2) | + 9 = ? 15
| 4(-1.5) | + 9
| -6 | + 9
6+9
15
and that also works.