Question

how do I find the instantaneous velocity for t=1 16t^2+105t

Answer 1

assuming 16t^2+105t represents the position function, you would differentiate 16t^2+105t with respect to t

then plug in t = 1 and evaluate

Answer 2

the time intervals (1,2) (1,1.5) (1,1.1) (1,1.01) (1,1.001)
average velocity 57 65 71.4 72.84 72.984

Answer 3

how are you getting that table?

Answer 4

i solved for the velocity given the intervals

Answer 5

the average velocity from t = 1 to t = 2 is 153 though, not 57

can you post your work?

Answer 6

yes let me try to copy it

Answer 7

is it possible to make it bigger?

Answer 8

if you copy and paste it into word i tried getting the picture as big and clear as possible

Answer 9

I tried that but it's very blurry and pixelated that I can't see much.

Answer 10

ok thanks for trying I appreciate it

Answer 11

try hitting printscreen and then pasting into MS paint

Answer 12

that should work