how do I find the instantaneous velocity for t=1 16t^2+105t

Question

jim_thompson5910 · Answer

assuming 16t^2+105t represents the position function, you would differentiate 16t^2+105t with respect to t

then plug in t = 1 and evaluate

anonymous · Answer

the time intervals (1,2) (1,1.5)  (1,1.1)  (1,1.01) (1,1.001)
average velocity    57       65      71.4     72.84       72.984

jim_thompson5910 · Answer

how are you getting that table?

anonymous · Answer

i solved for the velocity given the intervals

jim_thompson5910 · Answer

the average velocity from t = 1 to t = 2 is 153 though, not 57

can you post your work?

anonymous · Answer

yes let me try to copy it

anonymous · Answer

attachment

jim_thompson5910 · Answer

is it possible to make it bigger?

anonymous · Answer

if you copy and paste it into word i tried getting the picture as big and clear as possible

jim_thompson5910 · Answer

I tried that but it's very blurry and pixelated that I can't see much.

anonymous · Answer

ok thanks for trying I appreciate it

jim_thompson5910 · Answer

try hitting printscreen and then pasting into MS paint

jim_thompson5910 · Answer

that should work