Question

Molarity of standardized NaOH solution is 0.1012
final buret reading, mL IS 31.21
INITIAL buret reading, mL IS 15.72
VOLUME OF TITRANT, mL is 15.49
Moles of NaOH used is 1.568*10^-3 mol
Moles of HC2H302 neutralized by the NaOH is 1.568*10^-3 Mol
Molarity of dill HC2H302 is .0783
avearge molarity of diluted vinegar is 0.7865 M
the deviation di is .000350

How do i calculate the average deviation, D

Answer 1

the formula is \[\sum_{?}^{?}(x _{1}-x _{ave})/n\]

Answer 2

right

Answer 3

to caculate the average deviation, D

Answer 4

use the formula?

Answer 5

hi arronq how are you today

Answer 6

i'm okay, you?

Answer 7

im good i tried to plug in the numbers @aaronq

Answer 8

and?

Answer 9

what is the n stand for , like what do i put there

Answer 10

n is the number of data points (experimental values, \(x_i\)).

Answer 11

the x ave is 0.07865 right

Answer 12

yeah

Answer 13

so n is 4

Answer 14

casue we did 4 titration datas

Answer 15

sounds good

Answer 16

the experimental data points (values you got in the experiment)

Answer 17

the molarity of dill HC2H302 is .0783 for first data
.0785 for second data
.0789 for third data
.0789 for third data

Answer 18

and the averation devaition answer is supposed to be + or -____________ M

Answer 19

SO X1 IS

Answer 20

xi is each and one of those values

Answer 21

so do i add them up

Answer 22

no use the equation

Answer 23

and then plug in into the equation

Answer 24

you add up the differences

Answer 25

so .0783+.0785+..0789+.0789

Answer 26

right

Answer 27

no

(|.0783-0.07865|+|.0785-0.07865|+|.0789-0.07865|+|.0789-0.07865|)/n

Answer 28

ok

Answer 29

.000350
and .000150
.000250
.000250

Answer 30

so you add those then divide by n, which is 4

Answer 31

i get .001 if i add those up

Answer 32

right

Answer 33

divided by 4 is 2.5 E-4

Answer 34

okay, so thats the answer

Answer 35

IT IS .000250

Answer 36

is is + or - .000250

Answer 37

and how many sig figs

Answer 38

it's both, \(\pm\)

Answer 39

the sig figs in the answer should be the same as the value used in the calculation with the smallest number of sig figs

Answer 40

so + or - .00025 or +o or - .000250

Answer 41

the second

Answer 42

.000250

Answer 43

this one

Answer 44

yep, it's be a good idea if you wrote it in scientific notation

Answer 45

we have to find the average with average deviaton

Answer 46

is it .07865 + or - .000250 M

Answer 47

yeah that's it.

but these values .07865 + or - .000250 need to have the same number of decimal places

Answer 48

SO .07865 + or - .00025

Answer 49

i think it may be a problem that they both dont have same # of sig figs

hm i would round the average and write them in scientific notation

Answer 50

meaning

Answer 51

i not sure what you mean

Answer 52

would it be .7865 + or - .00025

Answer 53

\( 7.87*10^{-2} \pm 2.50*10^{-4} ~M\)

Answer 54

yeah isnt it the same as .07865 + or - .00025

Answer 55

not the same number of sig figs

Answer 56

no, zeroes on the left dont count

.07865 has 4

.00025 has 2

Answer 57

can you help me with finding the relative deviatioN, RD

Answer 58

is it the average deviation/average molarity/1000

Answer 59

so it is .000250 / 0.07865*1000

Answer 60

i think you're multiplying it by 100

Answer 61

weird. sure, i guess according to the formula you posted

Answer 62

so i get 3.178639542

Answer 63

the should be the same as the value with the least number of sig figs

Answer 64

no

.000250 has 3 sig figs

Answer 65

no

.000250 has 3 sig figs

Answer 66

i did .00025

Answer 67

okay, then thats it

Answer 68

yea

Answer 69

you just asked me this

Answer 70

how do i find this

Answer 71

help me find the molarity of original vinegar

Answer 72

in all the work me and my friend was helping me with

Answer 73

do you know i fin the molarity of original vinegar

Answer 74

molarity = mass/ volume

what is the molecular mass of vinegar?

Answer 75

60.06

Answer 76

can you give me time to read the problem?

Answer 77

what mass do you have in how much solution and then multiply by 100ml/60.06

Answer 78

What is your question?

Answer 79

ok so how much did you start with

Answer 80

volume of diluted vingar used in each titration is 20 mL 0.2 l

Answer 81

1.568*10^-3 * 60.06 =

Answer 82

bye

Answer 83

@aaronq