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find f^-1(x) of the equation. Will write the equation below:
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\[f(x)=-1+4\sqrt{8x-1} \] on the domain x>1/8
\[x=-1+4\sqrt{8y-1}\] solve for \(y\) which should not take too many steps
before we begin, is it \[\sqrt[4]{8x+1}\] or \[4\sqrt{8x+1}\]?
the second one
ok
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\[x=-1+4\sqrt{8y-1}\\ x+1=4\sqrt{8y-1}\\ \frac{x+1}{4}=\sqrt{8y-1}\\ \left(\frac{x+1}{4}\right)^2=8y-1\]
done in two more steps, add 1, divide by 8
|dw:1411007153016:dw| like that?
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