Question

Solve the following for all real equations: 6x^2+6x=1

Answer 1

rewrite it as

\[6x^2 + 6x + 1 = 0\]

now just use the general quadratic formula

\[x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\]

and from your question a = 6, b = 5 and c = 1

hope it helps...

the solutions are real but irrational

Answer 2

im going to try it right now

Answer 3

is the answer x= -1/2, -1/3?

Answer 4

and from your question a = 6, b = 5 and c = 1
right formula
b = 6

Answer 5

a = 6, b = 6 c = -1

Answer 6

aaaahhhhhhhhhhh how did you get that

Answer 7

@campbell_st has the correct formula but the values for a, b and c he made an error.
the equation is rewritten in the form ax^2 + bx + c =0 to pick up the values
6x^2+6x=1 6x^2 + 6x -1 = 0

Answer 8

when I did it the values for x were -3 + rt 3; -3 -rt 3

Answer 9

thank you

Answer 10

you need to redo with c = -1