What additional information would you need to prove that ΔABC ≅ ΔDEF by SAS? Triangle ABC is drawn with a single hash mark between A and B and triangle DEF is marked with a single hash mark between D and E. Angle B and angle E are marked congruent. segment AC ≅ segment EF segment BC ≅ segment FE segment AC ≅ segment FE segment BC ≅ segment EF (Adding the picture)
idk but hold on @undeadknight26
I would honestly say D. Not 100% sure though sorry.
can you tell me why??
bc is the same line as ef
Okay! Do you mind helping with a couple more?
If triangle ABC is congruent to triangle DEF, what would be the coordinate of F? Triangle ABC is shown. For triangle ABC, A is at 1, 0, B is at negative 1, 2, C is at 2, 3. Two other coordinates are shown. D is at 5, 0, E is at 3, 2. (6,3) (7,3) (6,4) (7,4)
I would say A because the figure is being pushed right 4 units. Since it is being pushed right the x would change and not the y. So it would be (6,3).
thank you that makes sense. 2 more?
Triangle CAT is transformed using a translation: Triangle CAT is shown. C is at 0, 0, A is at negative 2, 1, T is at negative 1, 4. Which could be coordinates of C'A'T' after the translation? C=(0,0), A=(2,1), T=(1,4) C=(2,0), A=(0,1), T=(1,4) C=(0,0), A=(-1,-2), T=(-4,-1) C=(-2,0), A=(-1,0), T=(-4,1)
I would say A...
Given: ΔABC ≅ ΔFDE What is the length of Segment line DE rounded to the nearest tenth? 3.2 4.2 2.2 3.6
the top is triangle then ABC then an = with a ~ on top then a triangle and FDE
No idea on this one mate.
ok
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