Help Please:)
Please show me the steps to get the answer that way i can do other problems like this
shiet
?what
do you know the formula for the midpoint?
square root of (x1-2)^2 + (y1-y2)^2
i think
no
midpoint = middle point that means it has to have a division of 2
The formula for the midpoint is this:\[mpt=(\frac{ x _{1}+x _{2} }{2 },\frac{ y _{1} +y _{2}}{ 2 })\]but you have some values to fill in for that. You have the fact that the midpoint is (5,-11), and you also have the fact that one of the coordinates is (3,5). So we will fill in our equation with that info.
\[(5,-11)=(\frac{ x _{1}+3 }{ 2 },\frac{ y _{1} +5}{ 2})\]
THANKS
Since the x coordinate of the midpoint is 5, if we set the x portion of our equation equal to 3, we can solve for x1. Like this: \[\frac{ x _{1} +3}{ 2 }=5\]
we can do the same with the y portion. The y coordinate of the midpoint is -11, so we will set the y portion of our equation equal to -11 in order to solve for y1. Like this:\[\frac{ y _{1}+5 }{ 2 }=-11\]
ok thank u
\[ \sf M = (\frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2})\] \[ \rightarrow (5, -11) = \frac{x_1 + 3}{2} , \frac{y_1+5}{2} \] \[\rightarrow 5 = \frac{x_1 + 3}{2}, -11 = \frac{y_1 + 5}{2}\]
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