Question

help pls! with this question -> with an average acceleration of -0.50m/s^2 to reach a speed of 12.0m/s. how long does it take for this acceleration to occur?

Answer 1

\[v=v_{o}+a \times t\]

Answer 2

12 = 0 - 0.5*t

Answer 3

24 seconds

Answer 4

Since it's -0.5 m/s^2 it's deceleration

Answer 5

If the object was going at 12 m/s to begin with, and it started decelerating at -0.5 m/s^2 - it would also take it 24 seconds to stop.

Answer 6

how do u get 24 ?

Answer 7

12 = 0.5*t /: 0.5
24 = t

Answer 8

With what speed does the object start? 0? not 0?

Answer 9

is -0.5

Answer 10

If it starts at rest, it's an illogical question.

Answer 11

mmmm still not getting it lol i suck on math

Answer 12

thanks anyways :)

Answer 13

Do you have the full question? or is that all they give you?

Answer 14

is all that they give me

Answer 15

lemme see if a get it so i have to subtract 0-(-0.5) divde by 12 right ?

Answer 16

according to the formula it's add, so the time will result in a negative number.

Answer 17

mkay thank you.