Question

Given f(x) = 9x-1 and g(x) = 1-x^2, find g(g(x))

Answer 1

we do not need f since it says to find g(g(x))

Answer 2

all g(g(x)) ,means is to replace the x's in g(x) with g(x)'s

Answer 3

so just insert it within itself

Answer 4

for if I said find g(f(x))
then you would do the following
g(f(x))=1-(f(x))^2

If I said find g(h(x))
then you do the following
g(h(x))=1-(h(x))^2


But you were asked to find g(g(x))

Answer 5

would it be... 1-(1-x^2)^2

Answer 6

yep yep

Answer 7

then you might have to do some multiplying

Answer 8

thanks!

Answer 9

we have 1-(1-x^2)^2

most teachers want that simplified

Answer 10

when the powers are like that do we add them or multiply?

Answer 11

so first take care of the (1-x^2)^2
which is (1-x^2)(1-x^2) <--- use foil

Answer 12

x^4 - 2x^2 +1

Answer 13

ok in front of all of that we had 1-( that )

Answer 14

1-(x^4-2x^2+1)

Answer 15

you are almost done @caligirl90

Answer 16

distribute that negative and then add the one set of like terms

Answer 17

x^4 +2x^2

Answer 18

well is that -x^4+2x^2?

Answer 19

oh yeah

Answer 20

you did very good

Answer 21

thanks