Ask
your own question, for FREE!
Ask question now!
Mathematics
18 Online
OpenStudy (mathmath333):
true or false
11 years ago
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (mathmath333):
\(\large\tt \color{black}{is~~ \sqrt x\times\sqrt y =\sqrt{xy} ~~for~~ x<0,y<0}\)
11 years ago
OpenStudy (acxbox22):
if \[\sqrt{7}\times \sqrt{6}=\sqrt{42}\] then what would you think tthe answer is?
11 years ago
OpenStudy (mathmath333):
false lol
11 years ago
OpenStudy (mathmath333):
so false?
11 years ago
OpenStudy (acxbox22):
no....let x=7 and y=6 xy=42 and 42 is under the radical so it is true
11 years ago
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (mathmath333):
ok what for the given condition
11 years ago
OpenStudy (mathmath333):
@acxbox22
11 years ago
OpenStudy (mathmath333):
@aum
11 years ago
OpenStudy (mathmath333):
@cj49
11 years ago
OpenStudy (freckles):
\[\sqrt{-9} \cdot \sqrt{-4}\]
it is for when both x and y are neg
so what does that equal @mathmath333
11 years ago
Join the QuestionCove community and study together with friends!
Sign Up
ganeshie8 (ganeshie8):
\[\large \sqrt{-1}\times \sqrt{-1} = i^2 \ne \sqrt{-1\times -1} = 1\]
11 years ago
OpenStudy (mathmath333):
oh thank, was confused
11 years ago
ganeshie8 (ganeshie8):
Most exponent properties have domain restrictions, for example :
\[\large \dfrac{\sqrt{x}}{\sqrt{y}} = \sqrt{\dfrac{x}{y}} \]
is also false if you don't specify the domain
11 years ago
OpenStudy (freckles):
if x,y<0
\[\sqrt{x}\sqrt{y}=i \sqrt{|x|} \cdot i \sqrt{|y|} =i \cdot i \sqrt{|x| \cdot |y|}=-1 \sqrt{|x||y|}=-1 \sqrt{|xy|} \]
11 years ago
OpenStudy (freckles):
or \[-\sqrt{|xy|}\]
11 years ago
Can't find your answer?
Make a FREE account and ask your own questions, OR help others and earn volunteer hours! Join our real-time social learning platform and learn together with your friends!
Sign Up
Ask Question