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Mathematics 18 Online
OpenStudy (mathmath333):

true or false

OpenStudy (mathmath333):

\(\large\tt \color{black}{is~~ \sqrt x\times\sqrt y =\sqrt{xy} ~~for~~ x<0,y<0}\)

OpenStudy (acxbox22):

if \[\sqrt{7}\times \sqrt{6}=\sqrt{42}\] then what would you think tthe answer is?

OpenStudy (mathmath333):

false lol

OpenStudy (mathmath333):

so false?

OpenStudy (acxbox22):

no....let x=7 and y=6 xy=42 and 42 is under the radical so it is true

OpenStudy (mathmath333):

ok what for the given condition

OpenStudy (mathmath333):

@acxbox22

OpenStudy (mathmath333):

@aum

OpenStudy (mathmath333):

@cj49

OpenStudy (freckles):

\[\sqrt{-9} \cdot \sqrt{-4}\] it is for when both x and y are neg so what does that equal @mathmath333

ganeshie8 (ganeshie8):

\[\large \sqrt{-1}\times \sqrt{-1} = i^2 \ne \sqrt{-1\times -1} = 1\]

OpenStudy (mathmath333):

oh thank, was confused

ganeshie8 (ganeshie8):

Most exponent properties have domain restrictions, for example : \[\large \dfrac{\sqrt{x}}{\sqrt{y}} = \sqrt{\dfrac{x}{y}} \] is also false if you don't specify the domain

OpenStudy (freckles):

if x,y<0 \[\sqrt{x}\sqrt{y}=i \sqrt{|x|} \cdot i \sqrt{|y|} =i \cdot i \sqrt{|x| \cdot |y|}=-1 \sqrt{|x||y|}=-1 \sqrt{|xy|} \]

OpenStudy (freckles):

or \[-\sqrt{|xy|}\]

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