Ask your own question, for FREE!
Mathematics 8 Online
OpenStudy (mathmath333):

http://prntscr.com/4m4be3

OpenStudy (mathmath333):

Every element of A is made greater than or equal to every element of B by adding to each element and integer x. then x cannot be less than

OpenStudy (mathmath333):

a. 2^10 b. the smallest value of B c. the largest value of B d. (max-min)

OpenStudy (mathmath333):

there is a paragraph for the question -->Directions of question 37-39

OpenStudy (cj49):

i guess it wud be max-min bt m not sure tho

OpenStudy (mathmath333):

ya it is , can u explain

OpenStudy (cj49):

i just used logic...to make A greater than B u need to add the diff of max-min to

OpenStudy (mathmath333):

if A={1,2,.......124} and B=(125,126.........250) how would u do it here

OpenStudy (cj49):

125-1=124 so ill add 124 to 1 i dun noe if m ryt nor not

OpenStudy (mathmath333):

@kirbykirby

OpenStudy (mathmath333):

@c

OpenStudy (mathmath333):

@campbell_st

OpenStudy (kirbykirby):

Did I not answer this before? o.O

OpenStudy (mathmath333):

the new question is in comments not the old one

OpenStudy (mathmath333):

Every element of A is made greater than or equal to every element of B by adding to each element and integer x. then x cannot be less than

OpenStudy (kirbykirby):

ah

OpenStudy (mathmath333):

a. 2^10 b. the smallest value of B c. the largest value of B d. (max-min)

OpenStudy (mathmath333):

its max - min in book can u tell how

OpenStudy (kirbykirby):

I find your example is a counter example to a, b, c. So, by elimination, you'd go with d :)

OpenStudy (mathmath333):

lol but i thought u would give me direct proof

OpenStudy (kirbykirby):

Lol. In the case of multiple choices, I find this is the easy way out obviously lol. To prove this directly... hmm I'd have to think about it a bit more lol

OpenStudy (mathmath333):

ok but i like ur cunningness here

OpenStudy (kirbykirby):

=] I try not the break my head if I don't have to hihi. But I'll see if I can come back to this a bit later. My thinking is a bit cloudy for proofs now lol

OpenStudy (mathmath333):

ok np

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!