Question

Show your work and write a short explanation with each calculation.

Part I:

Calculate the energy change (q) of the surroundings (water) using the enthalpy equation

qwater = m × c × ΔT.

We can assume that the specific heat capacity of water is 4.18 J / (g × °C) and the density of water is 1.00 g/mL.

The water has absorbed the heat of the metal. So, qwater = qmetal

Using the formula qmetal = m × c × ΔT, calculate the specific heat of the metal. Use the data from your experiment for the metal in your calculation.

Answer 1

Part II:

Calculate the energy change (q) of the surroundings (water) using the enthalpy equation

qwater = m × c × ΔT.

We can assume that the specific heat capacity of water is 4.18 J / (g × °C) and the density of water is 1.00 g/mL. Show ALL your work.

The water has absorbed the heat of the metal. So, qwater = qunknown metal

Using the formula qunknown metal = m × c × ΔT, calculate the specific heat of the metal. Use the data from your experiment for the unknown metal in your calculation. Show ALL your work.

Answer 2

I need an answer literally ASAP.

Answer 3

we need your data about mass of water, change of temperature, and mass of metal to be able to calculate the C of the metal

Answer 4

Mass of water would be for the KNOWN metal 25mL; Mass of the Metal would be 41.664g; and the temperature of the metal would be 100 degrees C and the temperature of the mixture would be 34.5 degrees C. I wasn't sure which of the last two that you needed.

Answer 5

For part 2: UNKNOWN METAL

The mass of the metal is 25.605
The temperature of the mixture is 29.1 degrees C
The temperature of the metal is 100 degrees C
The Mass of water would be 25mL

Answer 6

qwater = qmetal

q= m C ΔT
\[q=m _{1}C _{1}\Delta T=m _{2}C _{2}\Delta T\]
m1 and C1 are the water mass and heat capacity
m2 and C2 are the metal mass and heat capacity
the ΔT is the same in both side of the equation
\[m _{1}C _{1}=m _{2}C _{2}\]
\[C _{2}=\frac{ m _{1}C _{1} }{m _{2} }\]
\[C _{2}=\frac{ 25 g 4.18J/C }{41.664 g }\]= 2.51 J/C

Answer 7

Thanks you.