Question

Find a cubic function with the given zeros. 7, -3, 2

Answer 1

i keep getting x^3+6x^2-13x-42

Answer 2

but the answer choices r
f(x) = x3 - 6x2 - 13x - 42

f(x) = x3 - 6x2 + 13x + 42

f(x) = x3 - 6x2 - 13x + 42

f(x) = x3 + 6x2 - 13 + 42

Answer 3

x^3+6x^2-13x-42 solves to -7, 3 and -2

Answer 4

Instead of 7, -3, 2

Answer 5

f(x) = (x-7)(x+3)(x-2)

you have to turn the zeros into factors:

x=7 => x-7 = 0 x-7 is a factor

Answer 6

just have to multiply out to get the cubic you desire

Answer 7

ohh so i would really be (x-7) (x+3) (x-2)

Answer 8

im still not getting the answer

Answer 9

\((x-7)(x+3) =x^2-4x-21\) then multiply by (\(x-2)\)

Answer 10

so would is get f(x) = x3 - 6x2 + 13x + 42

Answer 11

nope, check your multiplication

Answer 12

sorry i was wrong f(x) = x3 - 6x2 - 13x + 42

Answer 13

there you go

Answer 14

thank you so much!!!

Answer 15

you're welcome