Question

determine c so that the function f(x)= 2cx+3 x<=1, and x^2+c x>1, is continous

Answer 1

plug x = 1 into 2cx+3 to get 2c*1+3 = 2c+3

also, plug x = 1 into x^2+c to get 1^2+c = 1 + c

Now equate those two parts: 2c+3 = 1+c

and solve for c to get your answer

Answer 2

\[ f(x) = \left\{
\begin{array}{lr}
2cx+3 & : x \leq 1\\
x^2+c& : x >1
\end{array}
\right.\]
just seeing if i could still do it

Answer 3

you can also use \begin{cases}

http://latex.wikia.com/wiki/Cases_%28LaTeX_environment%29

and you don't have to worry about having the "\right." in there (you still have to close off the cases though.

Answer 4

Thanks! Got it!