for the graph of the quadratic function, identify the coordinates of the vertex: f(x)=-3(x-4)^2+1 Please i need help

Question

anonymous · Answer

vertex is displayed for you 
it is 
$$f(x)=-3(x-4)^2+1$$ vertex is $(4,1)$

anonymous · Answer

so you just take the opposite sign of 4 and then 1 is the y?

imstuck · Answer

The vertex is in the form (x-h) and (y-k).  But yes, it is the opposite of the sign in front of what's inside the parenthesis.  and the +1 is the y.

anonymous · Answer

$$(x-4)^2$$ is always greater than or equal to zero, because it is a square
so $-3(x-4)^2$ is always less than or equal to zero
it is only zero if $x=4$

anonymous · Answer

therefore the very largest 
$$-3(x-4)^2$$ can be is zero, and if it is zero then 
$$-3(x-4)^2+1$$ is $1$ 
that makes the vertex $(4,1)$

anonymous · Answer

oh ok thank you both :)