(1)/(x-2)+(1)/(x+3)=7/6

Question

e.mccormick · Answer

$\dfrac{1}{x-2}+\dfrac{1}{x+3}=\dfrac{7}{6}$

So, solve for x.  First, you need to remember there is a restriction when things are on the bottomof a fraction.  Then you need to work on solving for x.

anonymous · Answer

@e.mccormick okay how do you get rid of the restriction?

e.mccormick · Answer

You can't.  It just means that solutions that make a fraction invaild (0 on bottom) are not corrrect.

anonymous · Answer

@e.mccormick   So i should get rid denominators ?

e.mccormick · Answer

Well, you have more than one fraction, so you need a common denominator first.

anonymous · Answer

@e.mccormick does the common denominator go into the 7/6 as well ?

e.mccormick · Answer

It can if you want to move it over fisrts, or you can leave that for cross multiplication.  Your choice.

anonymous · Answer

Oh okay thanks for the help  @e.mccormick

e.mccormick · Answer

np.  Let me know how it is going.

e.mccormick · Answer

Looks like a wholw number and a fraction.

e.mccormick · Answer

I also checked my answer on a graph.  Looks really good.  Let me know what you get and I can check it.  If you have a process problem, I have the details worked out.