Find the area of the larger segment whose chord is 8" long in a circle with an 8" radius. (Hint: A chord divides a circle into two segments. In problem 1, you found the area of the smaller segment.)

Question

anonymous · Answer

Area of a circle is pi times radius squared. so 8 squared is 64 times 3.14 is 200.96. 200.96 would be the approx. answer

anonymous · Answer

The answer has to be in this type of way: A=(XXX/X PI + XX sqrt X) in sq

cwrw238 · Answer

|dw:1411592675066:dw|

cwrw238 · Answer

you can find the area of smaller segment by finding the area of  the smaller sector - area triangle 
then subtract this from area of the circle

cwrw238 · Answer

the triangle is equilateral so the angle at the centre is pi/3 radians

cwrw238 · Answer

area of sector = 0.5 * r^2 * (pi/3)
area of triangle = 0.5 * 8*8* sin (pi/3)

cwrw238 · Answer

oh - i'm talking to myself again!