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jimthompson5910 (jim_thompson5910):
if you meant to say y(-2) and -2y, then they are the same
y(-2) means y times -2
-2y means -2 times y
you can multiply two numbers in any order which is why y(-2) = -2y
jimthompson5910 (jim_thompson5910):
however, y-2 is not the same as -2y
OpenStudy (anonymous):
i have to find the inverse of the function f(x) = 5x+2
jimthompson5910 (jim_thompson5910):
f(x) = 5x+2
y = 5x+2 ... replace f(x) with y
x = 5y + 2 ... swap x and y
now solve for y
OpenStudy (anonymous):
this is what i did but apparently is wrong...
f(x) = 5x+2
y = 5x + 2
y-2 = 5x
x = (y-2) / 5
x = (2-y) / 5
y = (2-x)/5
f^-1(x) = 2-x/5
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OpenStudy (ineedhelpfast12):
no they are not
OpenStudy (anonymous):
they are not wrong?
OpenStudy (anonymous):
nope they're different
jimthompson5910 (jim_thompson5910):
y-2 is not the same as y-2
OpenStudy (anonymous):
then how exactly do i do this? i'm not sure how to find the inverse of that equation
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jimthompson5910 (jim_thompson5910):
when you got to x = (y-2) / 5, you did it correctly
once you got to x = (2-y) / 5, you made your first mistake
jimthompson5910 (jim_thompson5910):
I would stop at x = (y-2) / 5 and call the inverse
\[\Large f^{-1}(x) = \frac{x-2}{5}\]
OpenStudy (anonymous):
oh i see what i did wrong!! thank you for the help!