Question

lim as x approaches -3 where f(x) is (x^4 -3x^2 +19x+3)/(x+3)

Answer 1

\[\frac{ x^{4}- 3x^{2} +19x+3 }{ x+3 } = \frac{ (x ^{3}-3x ^{2}+6x+1)(x+3) }{(x+3) } = (x ^{3}-3x ^{2}+6x+1)\]

Answer 2

Where are you getting the new numerator from.

Answer 3

Did you factor or something?

Answer 4

\[(-3)^{3}-3(-3) ^{2}+6(-3)+1 \] is your answer..

Answer 5

you have to divide.. to find out that form

Answer 6

yeah i did factorize.. do you know the method?

Answer 7

So like long division? and can you explain end behavior to me by any chance?