The height, h, of a falling object t seconds after it is dropped from a platform 300 feet above the ground is modeled by the function h(t)=300-16t^2 Which expression could be used to determine the average rate at which the object falls during the first 3 seconds of its fall? A.) h(3) – h(0) B.) h(3/3)-h(0/3) C.) h(3)/3 D.) h(3)-h(0)/3
I would LOVE to pick "D.", but you have written it incorrectly, so it is no longer the correct answer!
._. i tried the best i could to write it out.
do you understand how to do this problem?
No i do not.
You did not try the best you could. You could have added parentheses and done it correctly. D.) (h(3)-h(0))/3 Done! Now, the answer is D. h(3) is the location at time t = 3 - When we quit watching. h(0) is the location at time t = 0 - When it started. h(3) - h(0) is the total change in location. 3-0 = 3 is the time it took to change that much. So, [h(3) - h(0)]/3 is the average change over the 3 seconds that we cared about it.
you're a wingspan tkhunny
wingspan? no you're a c u. n,t
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