Question

help if u want medal

Answer 1

Using an electric kettle, 200g of water at 100 degree celsius is converted into steam at 100 degree celsius in 300 seconds.
The specific latent heat of steam is 2350J/g.
What is the average elecrical power uswed?

Answer 2

mass here is 200g =0.2 kg

Answer 3

The specific latent heat of steam is 2350J/g =2350 *1000 J/kg

Answer 4

options are
\[1)\frac{ 2250 }{ 300 \times 200 }W\]
\[2)\frac{ 200 \times 2250 }{ 300 }W\]
\[3)\frac{ 300 \times 2250 }{ 200 }W\]\[4)200 \times 300 \times 2250W\]

Answer 5

energy = 0.2 *2350 *1000 J
so power = energy /time
= 0.2 *2350 *1000 /300 J/sec

Answer 6

oh sorry its 2250J/g

Answer 7

yup

Answer 8

2nd option

Answer 9

i dont get a bit :(

Answer 10

first Heat energy = mass * latent heat
is it

Answer 11

Heat energy = mass * specific latent heat ( when there is achange in state of matter and temperature reamins constant )

Heat energy = mass * specific heat * change in temperature( when there is no change in state of matter and temperature changes )

Answer 12

so here
mass =200g =200 g
The specific latent heat of steam is 2250J/g.
so heat energy reauired is 200 *2250 J

Answer 13

now power = energy /time
= 200 *2250 J /300 sec
=200*2250/300 W

Answer 14

hope its clear to you now...