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Mathematics 8 Online
OpenStudy (anonymous):

2x+y^2)^5

OpenStudy (anonymous):

needs help asap

OpenStudy (anonymous):

try this http://www.cymath.com/answer.php

OpenStudy (anonymous):

did that help

zepdrix (zepdrix):

Hey Emond c: Need help expanding?

OpenStudy (anonymous):

yes

zepdrix (zepdrix):

\[\Large\rm (2x+y^2)^5\]

zepdrix (zepdrix):

When you expand you'll always have `one more # of terms` than the `power` on the binomial. Examples:\[\Large\rm (x+y)^1=x+y\qquad~\quad\qquad\qquad two~terms\]\[\Large\rm (x+y)^2=x^2+2xy+y^2\qquad three~terms\]

zepdrix (zepdrix):

So we'll have 6 terms after we expand:\[\large\rm (2x+y^2)^5=\text{___}+\text{___}+\text{___}+\text{___}+\text{___}+\text{___}\]

zepdrix (zepdrix):

Let's use this basic example to see what's going on:\[\large\rm (a+b)^5=\text{__}a^5b^0+\text{__}a^4b^1+\text{__}a^3b^2+\text{__}a^2b^3+\text{__}a^1b^4+\text{__}a^0b^5\]The exponent starts on the first term, and counts down. And counts up from 0 on the other term. The space is because we also end up with coefficients in front of each term.

zepdrix (zepdrix):

These coefficients come from Pascal's Triangle. You can instead use the Binomial Theorem if you prefer, but it's a little tedious.

zepdrix (zepdrix):

|dw:1411850042797:dw|This is the row that we want.

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