2x+y^2)^5
needs help asap
did that help
Hey Emond c: Need help expanding?
yes
\[\Large\rm (2x+y^2)^5\]
When you expand you'll always have `one more # of terms` than the `power` on the binomial. Examples:\[\Large\rm (x+y)^1=x+y\qquad~\quad\qquad\qquad two~terms\]\[\Large\rm (x+y)^2=x^2+2xy+y^2\qquad three~terms\]
So we'll have 6 terms after we expand:\[\large\rm (2x+y^2)^5=\text{___}+\text{___}+\text{___}+\text{___}+\text{___}+\text{___}\]
Let's use this basic example to see what's going on:\[\large\rm (a+b)^5=\text{__}a^5b^0+\text{__}a^4b^1+\text{__}a^3b^2+\text{__}a^2b^3+\text{__}a^1b^4+\text{__}a^0b^5\]The exponent starts on the first term, and counts down. And counts up from 0 on the other term. The space is because we also end up with coefficients in front of each term.
These coefficients come from Pascal's Triangle. You can instead use the Binomial Theorem if you prefer, but it's a little tedious.
|dw:1411850042797:dw|This is the row that we want.
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