Question

3 sqrt symbol 49 over 3 sqrt symbol 2 how do you slimpfy the expression completely ?

Answer 1

\[\frac{3\sqrt{49}}{3\sqrt{2}}\]
First cancel a 3 from numerator and denominator:\[\frac{\sqrt{49}}{\sqrt{2}}\]
Now simplify, given that the square root of 49 is 7:
\[\frac{7}{\sqrt{2}}\]
Now rationalize, multiplying numerator and denominator by the square root of 2:
\[\frac{7}{\sqrt{2}}*\frac{\sqrt{2}}{\sqrt{2}} = \frac{7\sqrt{2}}{2}\]
Notice that in the denominator the square roots cancel out because the square root of a number times itself is that original number.
So the answer is \[\frac{7\sqrt{2}}{2}\]