Question

net ionic equation for AgNO(aq) + K2SO3 (aq) including the reaction

Answer 1

When having to reactant, you create their products and balance the whole equation in order to complete the ionic equation. Without balancing the equation, you will miss the most essential information on finding the net ionic equation Here, you have the reaction of Silver Nitrate with Potassium Sulfite all in aqueous solution.

The positively charged elements (aka Cations) are combined with the negatively charged elements (aka Anions)

Silver Nitrate + Potassium Sulfite = Silver Sulfite + Potassium Nitrate

Here's the typical molecular equation
\[(2AgNO_3)_{(aq)} + (K_2SO_3)_{(aq)} = (Ag_2SO_3)_{(s)} + 2(KNO_3)_{(aq)}\]

Now, to get the ionic equation, break up the soluble strong electrolytes from the molecular equations into ions

Reactants
\[2Ag^+(aq)+2NO3^-_{(aq)}+2K^+(aq)+(SO_3)^{2-}_{(aq)}\]
Products
\[= (Ag_2SO_3)_{(s)} + 2K^+(aq)+2NO3^-_{(aq)}\]

If you find ions that are similar in both sides of the reactant and product, then eliminate those. The ions left will be the spectator ions and get the net ionic equation. And yay, you're done :)

If need help on finding the spectator ions, then let me know