Question

A 4 kg object is accelerated from rest to a
speed of 65.3 m/s in 55 s.What average force was exerted on the object during this period of acceleration?
Answer in units of N

Answer 1

We got \(v_{f}=v_{i}+a.t\)

\(v_{f}\) is the final speed, \(v_{i}\) is the initial speed,
\(a\) is the acceleration, \(t\) is the time

We had \(v_{f}\) = 65.3m/s, \(v_{i}\) = 0m/s, and \(t\) = 55s, you can now easily calculate the acceleration.

Next, \(F=m.a\), \( F\) is the force, \(m\) is the mass of the object, and \(a\) is the acceleration. We already knew that m = 4kg, and \(a\) was calculated above. Now you can calculate the force \(F\).