2H2 + O2 -> 2H2O How many grams of O2 and H2 were reacted to produce 30.0 g of H2O?
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\[2H_2+O_2\rightarrow 2H_2O\] As you can see, \(n_{H_2}=2n_{O_2}=n_{H_2O}\) First, calculate the amount of \(H_2O\). Now you get \(n_{H_2}=n_{H_2O}\), \(n_{O_2}=\frac{1}{2}n_{H_2O}\). You can easily calculate the mass of \(H_2\) and \(O_2\).
what do you mean by calculate the amount of H2O? Would that be 30g?
It is the amount of \(H_2O\) in moles. \(n=\frac{m}{M}\)
so 1.7 moles of H2O
Yes, about \(\frac{5}{3}\).
and now what do i do?
\(n_{H_2}=n_{H_2O}\)
would it be 1.7 mol H2 and 0.85 mol O2? :/
Correct. :)
so i would change that to grams by multiplying by the mass of H2 and O2?
Yes, the molar mass M.
Would it be 1.7mol H2 x 1g = 1.7g H2 0.85mol O2 x 16g = 13.6g O2 or 1.7mol H2 x 2g = 3.4g H2 0.85mol O2 x 32g = 27.2g O2
Actually the second one is correct. A hydrogen molecule is formed by two H atoms.
ok thank you.
It's my pleasure :)
Good explanation there tinyworm!
Thank you, @Preetha.
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