Question

Solve 2x^2 - 9x + 7 = 0 using an appropriate method. Show the steps of your work and explain why you chose the method used.

Solve 3x^2 - 12x + 2 = 0 by using a method different from the one you used in Part B. Show the steps of your work.

Answer 1

Pleasssseee help

Answer 2

Hmmm

Answer 3

@mathmale Can you please help me?

Answer 4

Can you factor an equation when the right side isn't equal to 0? Or are you not allowed to

Answer 5

I don't know. All I have is the information I already posted

Answer 6

Leave both equations as they are.
You have the following methods to choose from:
1) quadratic formula
2) factoring
3) factoring by grouping

Answer 7

You could try completing the square

Answer 8

In both cases you have 0 on the right side, so you can jump right in and attempt factoring.
4) completing the square is another very appropriate method. Thanks, Waffle.

Answer 9

@BassCatcher15 : Let's catch bass. Choose one of these four methods and show whatever steps of the process you can. Ask questions as appropriate.

Answer 10

@BassCatcher15 : Please factor x^2-2x+1, for practice.

Answer 11

I'm clueless right now

Answer 12

@mathmale

Answer 13

@Angel_Halo23

Answer 14

First Question: Use the cross factoring method, and get (2x-7)(x-1). Set 2x-7=0 and x-1=0. Solve each equation , getting you 7/2 and 1. So x=1, 7/2

Answer 15

yup negative one

Answer 16

Negative one? Huh?

Answer 17

yea i guess

Answer 18

Okay. So what about the second question?

Answer 19

hold on a min

Answer 20

Okayy. :)

Answer 21

:D hes here

Answer 22

Great!

Answer 23

What do you mean when you use ^ ? times? @BassCatcher15

Answer 24

@BassCatcher15

Answer 25

exponents

Answer 26

Yeah exponents. OS doesn't allow you to type the small exponent next to the base number, so we have to use the ^ symbol to show an exponent

Answer 27

Actually, OpenStudy DOES allow you to type in fancy math symbolism:\[2x^2 - 9x + 7 = 0\]