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Evaluate C(8, 8) help
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\[ \frac{8!}{8!(8-8)!}\]
That's from the definition of the combination formula
walk me trough the steps please
have you seen \(C(n, r)=\dfrac{n!}{r!(n-r)!}\) ?
no i never learned it im taking online class
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ok well that's the formula for \(C(n,r)\). And \(n!=n(n-1)(n-2)(n-3)\cdots(3)(2)(1)\) So example: \(4!=4(3)(2)(1)=24\) \(7!=7(6)(5)(4)(3)(2)(1)=5040\) Other results: \(1!=1\) and \(0!=1\) (defined to be that)
If you have something like \((6-2)!\), then you compute what's in parenthesis first, so \((6-2)!=4!=4(3)(2)(1)=24\)
thank you because the note they wee giving me i could not understand thanks !!!
your welcome :)
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