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OpenStudy (lilcathyx):

Pappy's Pond is located close to an elementary school. The city plans to fence it in to keep small children from accessing the water. What is the perimeter of a triangular-shaped fence the city can place around the pond, using integer coordinates (no decimals) on the grid? You must show all work to receive credit.

OpenStudy (lilcathyx):

OpenStudy (lilcathyx):

And i did this . what do you think ? @Ankh

OpenStudy (anonymous):

Now find the perimeter of the triangle you built using the distance formula. No need to use the formula on the base that is parallel to the x axis since its distance is pretty visible (12 units)

OpenStudy (anonymous):

Scratch what I said earlier about different coordinates, I misread what needs to be integer.

OpenStudy (lilcathyx):

Then im lost becuase the distance between AB is sq root of 72, which equals 8.5 & same for BC

OpenStudy (lilcathyx):

because*

OpenStudy (lilcathyx):

@Ankh

OpenStudy (lilcathyx):

We all have different coordinates for the triangle...does that mean my coordinates are wrong ?

OpenStudy (cj49):

nopes

OpenStudy (lilcathyx):

so then i would just add them ? like 8.5 + 8.5 + 12 = 29 ?

OpenStudy (cj49):

wat are ur coordinates

OpenStudy (lilcathyx):

A(10, 0) B(4, 6 ) C(-2, 0)

OpenStudy (cj49):

can u show ur work pls

OpenStudy (anonymous):

They asked for integer coordinates, not an integer perimeter.

OpenStudy (lilcathyx):

Work : AB (4-10)^2 + (6-0)^2 (-6)^2 + (6)^2 36 + 36 Sq root 72 = 8.5 BC (-2 -4)^2 + (0-6)^2 (-6)^2 + (-6)^2 36 + 36 sq root of 72 = 8.5

OpenStudy (lilcathyx):

AC is automatically 12

OpenStudy (lilcathyx):

@Ankh what do you mean integer coordinates ?

OpenStudy (anonymous):

A(10 , 2) is an integer coordinate A(10.234 , 2.123) isn't

OpenStudy (lilcathyx):

Ooohh. so what do i have to do ?

OpenStudy (anonymous):

What you did since the start was okay, just find the length of each edge and add them together to find the perimeter.

OpenStudy (lilcathyx):

the length of each edge ? so no distance formula ?

OpenStudy (lilcathyx):

@Ankh

OpenStudy (cj49):

use the distance formula

OpenStudy (lilcathyx):

didnt i do that already ?

OpenStudy (lilcathyx):

??

OpenStudy (cj49):

yes actually i din understood wat he meant acc to me u did fine.

OpenStudy (anonymous):

To find the length you need to use the distance formula. If you already did and found the lengths of each side, add them up to get the perimeter.

OpenStudy (anonymous):

How else would you find the length?

OpenStudy (lilcathyx):

Work : AB (4-10)^2 + (6-0)^2 (-6)^2 + (6)^2 36 + 36 Sq root 72 = 8.5 BC (-2 -4)^2 + (0-6)^2 (-6)^2 + (-6)^2 36 + 36 sq root of 72 = 8.5 8.5 + 8.5+ 12 =29 ?

OpenStudy (cj49):

yes its correct

OpenStudy (lilcathyx):

So thats all ?

OpenStudy (cj49):

yups

OpenStudy (lilcathyx):

Cool! Thanks you guys ! ^.^

OpenStudy (cj49):

yw c:

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