Solve for t. (100-t)^-4 I know it is simple but I completely blanked out on how to solve these. Dx
I'm not sure what you mean by solve since then isn't an equation.
You can solve equations. But there is no equation is what I'm saying.
sorry typo!!
I will it from the start since it deals with "weird" decimals. It should read: .1=.4-(3.9x10^-7)(100-t)^-5 **just realized I wrote -4 instead of -5...its been one of those days
\[0.1=0.4-(3.9 \cdot 10^{-7})(100-t)^{-5}\]
first thing i would do is subtract 0.4 on both sides
yes! and we gotta solve for t
\[0.1-0.4=-(3.9 \cdot 10^{-7})(100-t)^{-5}\]
After finding the difference of 0.1 and 0.4 I would then divide both sides by -(3.9*10^(-7))
do that for me and let me know what you have
**769230.77=(100-t)^-5
ok
\[0.1-0.4=-0.3\\-\frac{-0.3}{3.9 \cdot 10^{-7}}=\frac{3}{39} 10^{7}=\frac{1}{13}10^7 \\ \frac{13}{10^{7}}=(100-t)^5\]
so raise both sides to the 1/5th power
this is so we cancel that exponent 5 thing
okay got that but how do we get rid of that 5 exponent?
1/5*5=1
oh!
\[(\frac{13}{10^{7}})^\frac{1}{5}=(100-t)^{5\cdot \frac{1}{5}}\]
so t=99.934?
looks good \[t=100-(\frac{13}{10^7})^\frac{1}{5}\]
what an ugly answer
right? its for a mixing problem so it makes sense lol
i guess there are no pretty answers in the real world
you answer like all of my questions. I am so grateful!! lol
its np
are you a mathematician or a prof???
i have taught a little
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