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Chemistry 23 Online
OpenStudy (anonymous):

A 55.83 g sample of a substance is initially at 27.3 °C. After absorbing 1411 J of heat, the temperature of the substance is 109.7 °C. What is the specific heat (c) of the substance. c=______J/g Celcius

OpenStudy (cuanchi):

q=m x C x deltaT C= q /(m x delta T)

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