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OpenStudy (anonymous):

The following box plot shows the number of grams of carbohydrates in 12-ounces espresso beverage offered at Starbucks. What is the probability that a randomly Starbuck's Espresso has... Less than 27 grams of carbohydrates? More than 4.1 grams of carbohydrates?Please see attached file

OpenStudy (anonymous):

OpenStudy (kirbykirby):

It looks like 27 grams occurs at the median. And the median, by definition, is the point in your distribution that separates the data into 2 groups: 50% of the data lies below the median, and 50% of the data lies above the median. Based on this, hopefully it is clear what the probability that a randomly Starbuck's Espresso has less than 27 grams of carbohydrates. For the other part, it seems like about 9 grams in the minimum value in the sample. So, all data points lie at or above 9 grams. Furthermore, this implies that all data points lie above 4.1 grams. So, what is the probability of the that a randomly Starbuck's Espresso more than 4.1 grams of carbohydrates?

OpenStudy (anonymous):

@kirbykirby I do not have Idea about this

OpenStudy (kirbykirby):

If 27 grams is the median, and 50% of your data lies below the median. The the probability of having less than 27 grams would imply a probability of 50%

OpenStudy (kirbykirby):

does that make sense?

OpenStudy (anonymous):

I guess so @kirbykirby

OpenStudy (anonymous):

I just don't understand the second question, is there any solution for it? equation? @kirbykirby

OpenStudy (kirbykirby):

Well, the box plot implies that the minimum value is about 9 grams. So... if all of your data is 9 grams or more, then the probability of the sample having 9 grams or more of carbohydrates is 1. The probability is 1 because you are GUARANTEED that all your data lies above the 9-gram mark (i.e. you will ALWAYS find an espresso that has at least 9 grams of carbs). Now, 4.1 is smaller than 9, so if all your data is contained from 9 grams and above, then certainly all of your data is contained from 4.1 grams and above

OpenStudy (anonymous):

It should be 41.5, I am sorry type the question wrong

OpenStudy (kirbykirby):

oh... ok then.. that would be different for sure lol. Well the 41.5 mark looks like it is at the edge of the "box" right? And that line represents the 75th percentile... or also known as the 3rd quartile. That value means that 75% of your data is BELOW the 3rd quartile, and 25% of your data is ABOVE the 3rd quartile. This means that the probability of the finding an espresso with more than 41.5 grams (i.e. the probability of being above the 3rd quartile) is just 25%.

OpenStudy (anonymous):

i see

OpenStudy (anonymous):

make sense

OpenStudy (kirbykirby):

=]

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