The product of two positive numbers is greater than either number.
The product of two positive numbers is greater than either number.
How do i solve this I'm so confused.
Are there answer choices or no.
No. It just says find one counterexample to show that the conjecture is false
How about 1*2=2
Oh ok. Thank you. Im probably gonna ask more questions later on
You're welcome and ok.
\(\dfrac{1}{2}\times\dfrac{1}{2}\) is another counterexample.
Yeah
ok what about this one. The difference between two integers is less than either integer. What could I put?
first integer: 10 second integer: -10 difference: 20
Did this help?
No i dont get it. Explain
A counterexample is something the fulfills all the preliminary requirements, but not the conclusion. Try writing your question like this.... Given two integers A and B, A - B must be less than either A or B. Remember that an integer can be 0 or negative! So pick any positive integer and any negative integer. Try 5 and -7. Given two integers 5 and -7, 5 - -7 must be less than 5 or less than -7. But 5 - -7 is 12. There's your counterexample.
did that help
oh ok. Yes thank you. You really helping me lol
:) Your welcome
Do you have any other questions?
ok one more question. if it says that the sum of the first 100 positive even numbers, do i take 100* 101 to get my answer
because its going 1*2 2*3 ... so would i go 100*101 ?
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