Question

The first five terms of a sequence are shown below.

4, 7, 10, 13, 16

If the nth term of this sequence is represented by f(n), which of the following functions best represents this sequence?

f(n) = 3n - 1; n ≥ 1

f(n) = 3n + 1; n ≥ 1

f(n) = 4n - 1; n ≥ 1

f(n) = 4n + 1; n ≥ 1

Answer 1

@gorv

Answer 2

This is an arithmetic progression, with the first term 5 and common difference: 4.

The nth term of the sequence: a, a + d, a + 2d, a + 3d, ..... is:
a + (n-1)d

Answer 3

seee in each term multiplied by 3and 1 is added

Answer 4

first term
3*1+1=4

Answer 5

i think so to

Answer 6

second
3*2+1=7

Answer 7

3*3+1=10

Answer 8

The first term is a. Here a = 5.
The common difference is d. Here d = 4.
Put it in the formula for the nth term and simplify

Answer 9

so it will be
3n+1

Answer 10

It is simple to verify too. Just put n = 1, 2, 3, .... in 4n + 1 and see if you get each term of the sequence.

Answer 11

D

Answer 12

:)

Answer 13

A sequence has its first term equal to 3, and each term of the sequence is obtained by adding 5 to the previous term. If f(n) represents the nth term of the sequence, which of the following recursive functions best defines this sequence?

f(1) = 3 and f(n) = f(n - 1) + 5; n > 1

f(1) = 5 and f(n) = f(n - 1) + 3; n > 1

f(1) = 3 and f(n) = f(n - 1) + 5n; n > 1

f(1) = 5 and f(n) = f(n - 1) + 3n; n > 1

Answer 14

For the last question?
@woooooooooowwwww

Answer 15

oh what?

Answer 16

f(1)=3
f(n)= previous term +5
previous term = f(n-1)
f(n)=f(n-1)+5

Answer 17

???????

Answer 18

so it would be.......