Question

Newton's Second Law question, half way done just need some guidance!

Answer 1

You want to move a heavy box with mass 30.0 kg across a carpeted floor. You pull hard on one of the edges of the box at an angle 30 degree above the horizontal with a force of magnitude 240 N, causing the box to move horizontally. The force of friction between the moving box and the floor has magnitude 41.5 N . What is the box's acceleration just after it begins to move?

Answer 2

So I found the x acceleration:
applied force F=240N at an angle of 30degrees is = F cos 30 = 240 * 0.866 = 207.846 N
force of friction = 41.5 N
Normal force = 207.846 - 41.5 = 166.346 N
F= m * a and a = F / m = 166.346 / 30 = - 5.54487 m/s2

Answer 3

Just want to make sure it's correct and how to find the y component.