Question

Did I do this right? Finding Derivatives...

Answer 1

Derivative of \[f(x)=x^{2}cosx\]

Answer 2

product rule for sure

Answer 3

I got \[-\sin^{3}x-2\cos^{2}x\]

Answer 4

hhhmm no

Answer 5

\[\left(fg\right)'=f'g+g'f\] with
\[f(x)=x^2, f'(x)=2x,g(x)=\cos(x), g'(x)=-\sin(x)\] make a direct substitution

Answer 6

\[(x^{2})(-sinx)-(cosx)(2x)\]

Answer 7

second minus should be a plus

Answer 8

oops

Answer 9

\[-x^2\sin(x)+2x\cos(x)\] is the nice way to make it look

Answer 10

Do I simplify further

Answer 11

i wouldn't, no
you can factor out an x if you like, no real reason to do so

Answer 12

ohhh ok thanks :)

Answer 13

yw