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R(p)=1200p=25p^2. Find the unit price that will yield maximum revenue. What is the maximum revenue?
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i think it should be R(p)=1200+25^2 ???
helloooo @yoitsren waiting for u to rplyyyy buddy
sorry, I was away for awhile! I wrote the equation the way it was written in my assignment
r(p)=1200p it means it can generate infinite amount of revenue
1200p=25p^2 1200p/25=p^2 48p=p^2 p^2-48p=0 differentiate it 2p-48=0 p=48/2=24 p=24
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at this value revenue will be max
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