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What is the equation in standard form of the line which passes through (4, –2) and has a slope of –3?
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@Fanduekisses <3<3
You need to use the point slope formula
\[y-y_{1}=m(x-x_{1})\]
Plug in what you were given
Jesus thats confusing oh dear lord
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m = rise/run ??
yes, m = slope which in this case is -3
What about 4, -2?? I'm sorry this is very confusing >.<
remember (x,y) so x=4 and y = -2
but plug them in the\[x_{1} and y _{1} \]
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\[(y--2)=-3(x-4) \]
Simply/ distribute
then get it in standard form which is in Ax + By + C = 0
After simplifying you should have: \[y+2=-3x+4\]
then get it in standard form
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What would be standard form exactly ?
???
No, the standard form is Ax+Bx= C
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