Question

Find the equation of the line tangent to the graph of f at (1,-4), where f is given by f(x)=6x^3−13x^2+3. Use y as the dependent variable when you write your equation.

Answer 1

f(x)=6x^3−13x^2+3
Find f'(x)
Then evaluate f'(1).
That will be the slope 'm' of the tangent.
Plug it into y = mx + b
And since (1,-4) is a point on it, put x = 1 and y = -4 and find b.

Answer 2

ok, thanks! Ill try and work it out from here.

Answer 3

You are welcome.

Answer 4

I got y=-8x+4 is that the answer or is there something else to do?

Answer 5

Yes, that is what I am getting too.

Answer 6

ok, perfect! Thanks!!!

Answer 7

yw.