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OpenStudy (anonymous):
Evaluate https://wca.sooschools.com/media/g_alg02_ccss_2013/11/img_alg02u11c02q08d_12.gif
The value of this expression is
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OpenStudy (anonymous):
@amistre64
OpenStudy (anonymous):
@tHe_FiZiCx99
OpenStudy (anonymous):
@Aimee98
OpenStudy (anonymous):
\[\sin^2(x)(1-\cos^2(x))=\sin^2(x)\sin^2(x)=\sin^4(x)\]
OpenStudy (anonymous):
if that is an exponent of \(-1\) outside, then it is
\[\frac{1}{\sin^4(x)}\]
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OpenStudy (anonymous):
Thank you. Can you help me with one more question?
OpenStudy (anonymous):
sure
OpenStudy (anonymous):
btw the last one can be written as
\[\csc^4(x)\]
OpenStudy (anonymous):
cotθ
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OpenStudy (anonymous):
ok
OpenStudy (anonymous):
\[\cos^2(x)=\frac{1}{4}\]
\[\cos(x)=\pm\frac{\sqrt2}{2}\]
OpenStudy (anonymous):
since you are in quadrant 3 it is negative, so
\[\cos(x)=-\frac{\sqrt2}{2}\] making \(x=\frac{5\pi}{4}\) if you are working in radians
OpenStudy (anonymous):
Thanks
OpenStudy (anonymous):
then you can find \[\cot(\frac{5\pi}{4}) \] right?
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OpenStudy (anonymous):
no
OpenStudy (anonymous):
is it 225?
OpenStudy (anonymous):
@satellite73
OpenStudy (anonymous):
@satellite73
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