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Mathematics 13 Online
OpenStudy (anonymous):

Evaluate https://wca.sooschools.com/media/g_alg02_ccss_2013/11/img_alg02u11c02q08d_12.gif The value of this expression is

OpenStudy (anonymous):

@amistre64

OpenStudy (anonymous):

@tHe_FiZiCx99

OpenStudy (anonymous):

@Aimee98

OpenStudy (anonymous):

\[\sin^2(x)(1-\cos^2(x))=\sin^2(x)\sin^2(x)=\sin^4(x)\]

OpenStudy (anonymous):

if that is an exponent of \(-1\) outside, then it is \[\frac{1}{\sin^4(x)}\]

OpenStudy (anonymous):

Thank you. Can you help me with one more question?

OpenStudy (anonymous):

sure

OpenStudy (anonymous):

θ is in Quadrant III and https://wca.sooschools.com/media/g_alg02_ccss_2013/11/img_alg02u11c01q08d_07.gif A. Evaluate cotθ. B. In two or more sentences, explain how to find the value of cotθ.

OpenStudy (anonymous):

btw the last one can be written as \[\csc^4(x)\]

OpenStudy (anonymous):

cotθ

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

\[\cos^2(x)=\frac{1}{4}\] \[\cos(x)=\pm\frac{\sqrt2}{2}\]

OpenStudy (anonymous):

since you are in quadrant 3 it is negative, so \[\cos(x)=-\frac{\sqrt2}{2}\] making \(x=\frac{5\pi}{4}\) if you are working in radians

OpenStudy (anonymous):

Thanks

OpenStudy (anonymous):

then you can find \[\cot(\frac{5\pi}{4}) \] right?

OpenStudy (anonymous):

no

OpenStudy (anonymous):

is it 225?

OpenStudy (anonymous):

@satellite73

OpenStudy (anonymous):

@satellite73

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